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	<title>Baltimore Dorkbot &#187; range finders</title>
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	<description>People doing strange things with electricity, hon.</description>
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		<title>Maps of distances from range finders?</title>
		<link>http://bmoredorkbot.org/2009/06/maps-of-distances-from-range-finders/</link>
		<comments>http://bmoredorkbot.org/2009/06/maps-of-distances-from-range-finders/#comments</comments>
		<pubDate>Wed, 03 Jun 2009 21:38:28 +0000</pubDate>
		<dc:creator>LesBradley</dc:creator>
				<category><![CDATA[General discussion]]></category>
		<category><![CDATA[images]]></category>
		<category><![CDATA[mapping]]></category>
		<category><![CDATA[range finders]]></category>

		<guid isPermaLink="false">http://bmoredorkbot.org/?p=107</guid>
		<description><![CDATA[I&#8217;ve been doing homework with lots of search strategies, but still looking for some answers.
I would like a range finder to draw a two-dimensional map that represents the distances of everything within its field of view.  It would look as if you were using a video/still camera, shooting what&#8217;s in front of, say, my [...]]]></description>
			<content:encoded><![CDATA[<p>I&#8217;ve been doing homework with lots of search strategies, but still looking for some answers.<br />
I would like a range finder to draw a two-dimensional map that represents the distances of everything within its field of view.  It would look as if you were using a video/still camera, shooting what&#8217;s in front of, say, my robot, but the picture would not be displaying the varying brightness of light reflected from objects.  Rather, there would be, perhaps, a gray-scale image based on distances observed by a range finder.<br />
This would probably require a scanning of the scene (as a video camera would do) rather than the single horizontal line that (I believe) a typical range finder would yield.<br />
Anybody work with such concepts or have suggestions?  I&#8217;ve been searching literature on surveying, photogrammetry (!), autonomous vehicle navigation, and the like.  I&#8217;m just hoping to find a relatively simple solution; somebody must have done this before.<br />
Les Bradley</p>
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